Question

PLS SOLVE AND HELPPPPPPPPP




PLS PLS PLS​

Answer 1

Step-by-step explanation:

If tan theta = 3/4, then what is the value of sin theta and sec theta?

Let theta = x

tan x=3/4. , sin x=? and. sec x=?

sec^2x=1+tan^2x=1+9/16= 25/16

sec x=+/-(5/4). Answer

cos x= +/- 4/5

sin x=+/-√(1-cos^2x) = +/- √(1–16/25)=+/- √(9/25) = +/-3/5. Answer.

Second-method:-

tan x= 3/4

or. sin x/cos x= 3/4

or. (sin x)/3= (cos x)/4 =k(led)

or. sin x= 3k. , cos x=4k

sin^2x+cos^2x=1. =>. 9k^2+16k^2=1. or. 25k^2 = 1

k = +/-1/5

sin x= 3k = +/-3/5. Answer

and. cos x=4k = +/-(4/5). or sec x= +/-(5/4). Answer.