pls solve fast..........
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OB^2= AB^2 + OA^2 (Pythagoras theorem)
OB =10√2 cm
So, r=10√2cm
ar quadrant = 1/4 × π×r^2
=157 cm^2
ar square = side × side
=100 cm^2
ar shaded region =ar quad - ar square
(157 - 100)cm^2
=57 cm^2
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