Question

Pls solve fast and i will definitely mark you. Factorise a⁴x²- 2a³x + a² with steps​

Answer 1

Answer:

a^4 -2a^3x+a^2=

(p=a6x2)

a4x2-a3x-a3x+a2=

a3x(ax-1)-a2(ax-1)

=

(a^3x-a^2)(ax-1) is the factorised form

Answer 2

Answer: a²(ax-1)²

Step-by-step explanation

First of all, we do notice that they all have something in common, a².

So...

a²(a²x²-2ax+1)

From here onwards, we can now factorise what's inside the brackets.

[ax²+bx+c]

(a²x² -2ax +1)

a= a²

b= -2a

c= 1

ac= a²

a² can be -a × -a

a²x² -ax -ax +1

Notice how I made the -2ax into -ax and -ax. You can only do this if your ac is a² and any two numerals or symbols that multiply each other to get it which also when that one numeral subtracts the other one numeral to get b. (complicated part, ask me to clarify if u don't understand)

Anyways,

a²x² -ax -ax +1

ax(ax -1) -1(ax-1)

(ax-1)²

And remember the a² we took out earlier, add that

a²(ax-1)²

Done! ^_^.