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a body projected vertically upward with velocity 20 metre per second returns to the ground with velocity 16 metre per second then the maximum height attained by the body is (41 / 20)xN and then the value of N is
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Answer:
Consider the downward direction to be positive.
Acceleration due to gravity =g
Initial velocity =−u
Final velocity v=0
∴ v
2
−u
2
=2(−g)H
Or 0−u
2
=−2gH
⟹ H=
2g
u
2
We get that H∝
u
2
Thus maximum height attained becomes four times (4H) when the initial velocity is increased by 2 times.
Explanation:
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