Question

pls solve fast no irrelevant and pls​

Answer 1

Step-by-step explanation:

let k' be any constant >0, k=logk', k>0

2^x=3^y=12^z = k'

2^x =k'

log2^x= k (log a^b= bloga)

xlog2 = k

log2 =k/x ---A

3^y = k'

log3^y =k

ylog 3 =k

log3 =k/y ----B

12^z = k'

zlog12 =k

zlog(2^2×3)=k (logab = log a +log b)

z(2log2+log3)=k

2log2 + log3= k/z

Substitute A,B in above equation

2×k/x + k/y =k/z

k(2/x +1/y)= k/z

dividing with k on both sides

2/x+1/y =1/z

hope this helps