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1
CORRECT OPTION IS D
Position of car P x
p
(t)=at+bt
2
Thus velocity of car P v
p
=
dt
d[x
p
(t)]
=a+2bt
Position of car Q x
Q
(t)=ft−t
2
Thus velocity of car Q v
Q
=
dt
d[x
Q
(t)]
=f−2t
According to the question, v
p
∣
∣
∣
∣
∣
t=t
o
= v
Q
∣
∣
∣
∣
∣
t=t
o
∴ a+2bt
o
=f−2t
o
⟹t
o
=
2(b+1)
f−a
Answered by
1
Answer:
the right and is an option(d)
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