pls solve fast pls with explanation.... thank you
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√8 = 2√2 , √18 = 3√2 , √32 = 4√2
Now sequence = 2√2 , 3√2 , 4√2 ,......
common difference(d) = a2 - a1 = 3√2 - 2√2 = √2 , first term (a) = 2√2
∴ 4th term of an AP = a + 3d = 2√2 + 3(√2) = 5√2
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