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Question:-
Examine, if 2160 is a perfect cube. If not find the smallest number by which it must be divided so that the quotient is a perfect cube. Also find the cube root of new cube number.
Answer:-
Taking LCM of 2160 we get,
5 |2160
3 |432
2 |144
2 |72
2 |36
2 |18
3 |9
3 |3
|1
⟶ 2160 = (2 × 2 × 2) × (3 × 3 × 3) × (5 × 2)
We observe that,
2 , 3 exist in a group of three but 5 × 2 does not.
So, 2160 is not a perfect cube.
So, 2160 should be divided by 10 , to get a quotient which is a perfect cube.
⟶ 2160/10 = 216.
Now,
LCM of 216 is ,
3 | 216
3 |72
3 |24
2 |8
2 |4
2 | 2
| 1
⟶ 216 = (3 × 3 × 3) × (2 × 2 × 2)
⟶ ³√216 = ³√(3)³ × (2)³
⟶ ³√216 = ³√(3 × 2)³
⟶ ³√216 = 6
∴
- The smallest number by which 2160 is divided to get a perfect cube is 10.
- Cube root of the new cube number is 6.
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