pls solve
if. f(x)=x^2-3x
then the points at which f(x)=f'(x) are
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2x-3=x²⁻3x
x²⁻5x+3=0
x=(5±√(25-12))÷2
=(5±√13)/2
x²⁻5x+3=0
x=(5±√(25-12))÷2
=(5±√13)/2
hypste:
thnx
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