Question

Pls solve If two zeroes of the cubic polynomial  x3 + x2  are zero each , then the third zero is​

Answer 1

Answer:

-1

Step-by-step explanation:

${x}^{3} + {x}^{2} = {x}^{2} (x + 1) \\ {x}^{2} (x + 1) = 0 \: \: (to \: find \: zero) \\ x = 0 \: or \: - 1$

So, the required answer is -1.

Answer 2

Step-by-step explanation:

If two of the zeros of cubic polynomial

${x}^{3} + {x}^{2} = 0 \\ \\ are \: 0$

the third zero is

${x}^{2} (x + 1) = 0 \\ \\ {x}^{2} = 0 \\ \\ x_1 = 0 \\ \\ x_2 = 0 \\ \\ x + 1 = 0 \\ \\ x_3 = - 1$

So,its third zero will be -1.

Hope it helps you.

Note: Three zeros are represented by x1,x2 and x3.