Question

pls solve ill make u brainlist

Answer 1

Given,

There are 2 triangles given within a triangle i.e. ∆PQS and ∆PRS.

angle Q = 60°

angle R = 40°

angle QPS = 55°

$\underline{\mathbf{Property \: used :}}$

• Sum of all angles of a triangle is equal to 180°

So,

In ∆PQS

angle PQS + angle QPS + angle QSP = 180°

60° + 55° + angle QSP = 180°

angle QSP = 180° - 115°

angle QSP = 65°

i.e. a = 65°

QS is a linear pair

So,

a + b = 180°

65° + b = 180°

b = 180° - 65°

b = 115°

In ∆PRS,

angle PRS + b + c = 180°

40° + 115° + c = 180°

c = 180° - 155°

c = 25°

Hope it helps! ;)