Math, asked by bhavanash, 10 months ago

pls solve it........​

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Answers

Answered by sonaliderdekar17
1

Step-by-step explanation:

Total height of tank is 6m

Therefore the height of cylinder is

(6)-(1)-(1).......if we minus the both heights of hemisphere...

=4m

Then use the formula of volume of cylinder

Which is pier^2h

=3.14×1×1×4

=3.14×4

=12.56m^3

Now the volume of hemispher is

2/3pie r^2h

=2/3 × 3.14 ×1×1×1

=6.28/3

=2.093m^3

There are 2 hemisphere

Therefore

2×2.093

=4.186m^3

Adding both we get

12.56+4.186

=16.746m^3

This is answer

Please mark me brainliest

Answered by rakesh7860R
1

Answer:

This Question seems to be difficult but it is really a good question. You can solve this as follows:-

Step-by-step explanation:

We have ;

Radius = 1 m

Height = 6 m ( Tank) height (cylinder)= 6 - 2 = 4 m

Maximum quantity of milk filled = Volume of cylinder+ 2 Volume of Hemispheres

= πr²h + 2 × ( 2/3πr³ + 2/3πr³ )

= 22/7 × 1² × 4 + 2 × ( 2/3 × 22/7 × 1³ + 2/3 × 22/7 × 1³)

= 88/7 + 2 × ( 44/21 + 44/21 )

= 88/7 + 176/21

= 440/21

= 21 m³ Approx

We know, 1m³ = 1000 litre

21 = 21 × 10³ litre

= 2.1 × 10 litres

Now,T.S.A of tank =2πr(r+h) + 2πr² + 2πr²

= 2×22/7× 1(1+6) + 4πr²

= 44/7 × 7 + 4 × 22/7 × 1²

= 44 + 88/7

= 396/7

= 56.57 m³ ( approx)

So, Volume in litres = 2.1 × 10⁴ litres

T.S.A of tank = 56.57

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