Question

pls solve it...................​

Answer 1

ANSWER:

GIVEN:

• 1st Resistance = 6 Ω
• 2nd Resistance = 6 Ω
• 3rd Resistance = 6 Ω

TO FIND:

• How would we connect the resistance to get resultant as 9 Ω and 4 Ω.

SOLUTION:

To get 9 Ω equivalent Resistance:

We should connect two 6 Ω resinstance in parallel then one 6 Ω resistance in series with the parallel combination.

$\: \implies \:\dfrac{1}{r \: (parallel)} = \dfrac{1}{6} + \dfrac{1}{6} \\ \\ \implies \: \frac{1}{r(parallel)} = \dfrac{2}{6} \\ \\ \implies \: \frac{1}{r(parallel)} = \dfrac{1}{3} \\ \\ \implies \: r(parallel) = 3 \Omega \: \\ \\ \: now \: one \: 6 \Omega \: resistance \: are \: connected \: in \\ \: series \: with \: two \: 6 \: \Omega \: resistance \: connected \\ \: in \: parallel .\: \\ \\ equivalent \: resistance \: = 6 \Omega \: + 3\Omega \: \\ equivalent \: resistance \: = 9 \Omega \: \:$