Question

pls solve it fast....
(3/4)^3 (4/3)^(-7) = (3/4)^2x
find the value of x​

Answer 1

Hello dude❤️❤️❤️❤️

Answer:

X=5

Step-by-step explanation:

(3/4)^³ × (4/3)^-7 = (3/4)^2x

[ a^-1 = 1/a^1 ]

(3/4)^3 × (3/4)^7 = (3/4)^2x

[a^m × a^n = a^m+n]

(3/4)^3+7 = (3/4)^2x

(3/4)^10 = (3/4)^2x

Here, bases are equal, so the powers must be equal!

10 = 2x

x = 10/2

x = 5

Hope it's helpful ❤️❤️❤️

Answer 2

Answer:

here is your answer

have a good day