Question

pls solve it fast.......​

Answer 1

Step-by-step explanation:

here, ABCD is a Parallelogram, E and F are the mid-points of sides AB and CD respectively.

Therefore, AB║EF║BC

The line PQ intersects the line segments AD, EF and BC at P, O and Q respectively.

We need to prove that PO = OQ.

Now, If three or more parallel lines intersect a transversal, then they cut off the transversal proportionally.

here, AD, EF and BC are three parallel lines and PQ is the transversal.

∴ $\frac{AE}{EB} = \frac{CF}{DF} = \frac{PO}{OQ}$

Since E and F are mid-points of AB and CD respectively, we have,

AE = EB and CF = DF

⇒ $\frac{PO}{OQ} = 1$

⇒ PO = OQ         proved.

hope it will help you.

Answer 2

Answer:

PO

----- = 1

OQ

Step-by-step explanation:

I hope it's help you