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given
perimeter of rectangle = area of rectangle
2( L+ b) = L×b ----(1)
breadth (b) = 2whole 3/4 = 11 /4 cm
from(1)
2(L + 11/4) = L× 11 /4
2L = L11 /4 - 22 /4
8L -11L = = -22
-3L = -22
L = 22 /3 cm
L = 7whole 1 / 3 cm
hence the length of rectangle (L)
= 7whole 1/3 cm
◆hope it helps ◆
perimeter of rectangle = area of rectangle
2( L+ b) = L×b ----(1)
breadth (b) = 2whole 3/4 = 11 /4 cm
from(1)
2(L + 11/4) = L× 11 /4
2L = L11 /4 - 22 /4
8L -11L = = -22
-3L = -22
L = 22 /3 cm
L = 7whole 1 / 3 cm
hence the length of rectangle (L)
= 7whole 1/3 cm
◆hope it helps ◆
TheLostMonk:
thank you ,its 1 whole 7/3 cm in mixed fraction
thanks alot
wc
ooh sorry its 7 whole 1/3 in mixed fraction
Answered by
1
2(l+b) = lxb
2(l+11/4) = l x 11/4
l+11/4=11l/8
11/4=11l/8 - l
11/4= 3l/8
on further simplification
l=22/3
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