Pls solve it for brainliest answer....... For sure!!!!
8th one
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By the angle sum propertiy of a triangle...
A+B+C=180°
→A+B=180°-C →(1)
Substituting (1) in the given equation
Tan [ (A+B)/2]=
=Tan [(180°-C)/2]
=Tan [ (180/2) -C/2]
=Tan[90°- (C/2)] [ tan (90-a)=cot(a)]
=Cot[C/2]
Hope it Helps...
Regards,
Leukonov...
A+B+C=180°
→A+B=180°-C →(1)
Substituting (1) in the given equation
Tan [ (A+B)/2]=
=Tan [(180°-C)/2]
=Tan [ (180/2) -C/2]
=Tan[90°- (C/2)] [ tan (90-a)=cot(a)]
=Cot[C/2]
Hope it Helps...
Regards,
Leukonov...
VardhanL:
thx a lot
Answered by
1
As we know
A +B +C =180
Then
tan(A+B/2) = tan (180-C/2) = tan(90-[C/2])
= cot C/2
hope you understand
Thank You
Regards
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