Question

pls solve it for me​

Answer 1

Answer:

$({x}^{2} - x) - \frac{ 1}{2} (x - 3 + 3 {x}^{2} ) \\ \\ \\ = > 2 {x}^{2} - 2x - x + 3 - 3 {x}^{2} = 0 \\ \\ = > - {x}^{2} - 3x + 3 = 0 \\ \\ \\ = > {x}^{2} + 3x - 3 = 0 \\ \\ \\ x(x + 3) = 3 \\ \\ x = 3 \\ x = - 3$

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Answer 2

Answer:

aa gya

Step-by-step explanation:

=(x^2-x) -1/2(x-3+3x^2)

=(x^2-x) -x/2+3/2-3x^2

=-x^2/2-x/2-x+3/2 (answer)