Question

Pls solve it for me fasttt

Answer 1

AsPOR = 130

As we know any chord subtends double angle at center than at any point on circumference

So RT is subtending angle POR = 130

So <S becomes = 130/2 = 65

Now as <POR + <POQ = 180

So POQ = 180 - POR = 180 -130 = 50

in POQ

POQ = 50

OQP = 90

so <1 = 180-(90+50)= 180 - 140= 40

So

<1 + <2= 40+ <S = 40 + 65 = 105


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Answer 2

Answer:

Step-by-step explanation:

∠POR=130

in ΔPOQ

∠1+∠Q=∠POR                     .................................AS EXTERNALANGLE O A Δ

∠1+90=130            ..AS ∠Q IS ANGLE FORMED BY RADIUS AND TANGENT

∠1=40

∠RST=1/2∠POR               ..............................AS ANGLE FORMED BY SAME ARC

∠2=1/2×130

∠2=65

∠1+∠2=65+40=105

HENCE PROVED

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