Question

pls solve it . In this we have to do factorisation

Answer 1

➡HERE IS YOUR ANSWER⬇

${a}^{3} + 3 {a}^{2} b + 3a {b}^{2} + {b}^{3} - 8 \\ \\ = ( {a}^{3} + 3 {a}^{2} b + 3a {b}^{2} + {b}^{3} ) - 8 \\ \\ = {(a + b)}^{3} - {2}^{ 3} \\ \\ = (a + b - 2)( {( a+ b})^{2} + 2(a + b) + {2}^{2} ) \\ \\ \\ formula \: \\ \\ {a}^{3} - {b}^{3} \\ \\ = (a - b)( {a}^{2} + ab + {b}^{2} )$

⬆HOPE THIS HELPS YOU⬅

Answer 2

I hope this will help you