pls solve it. it's maths huhu
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Step-by-step explanation:
A does (1/20)th of the work in 1 day.
B does (1/30)th of the work in 1 day.
C does (1/40)th of the work in 1 day.
In the first 4 days, A, B and C did 4[(1/20)+(1/30)+(1/40)] =4{6+4+3]/120 = 13/30th of the work.
In the next 2 days, B and C did 2[(1/30)+(1/40)] = 2*7/120 or 7/60th of the work.
So in the first 6 days the work done was (13/30)+(7/60) = (26+7)/60 = 33/60 or 11/20th of the whole. What remained to be don after the first 6 days was (9/20)th of the whole.
The remaining (9/20)the was done by C alone in (9/20)*(40/1) = 18 days.
Thus the whole work is done in 24 days from the start. Answer.
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