Question

pls solve it it's urgent

Answer 1

Hello there!

You can factorise the given equation in the following way:

$= 2 \sqrt{2} {a}^{3} + 3 \sqrt{3} {b}^{3} + 6 \sqrt{3} {a}^{2} b + 9 \sqrt{2} a {b}^{2} \\ = {( \sqrt{2} a)}^{3} + {( \sqrt{3}b )}^{3} + 3( \sqrt{2} a)( \sqrt{3} b)( \sqrt{2} a + \sqrt{3} b)$

You can see that this is the standard form of the expansion of (X+Y)^3. Hence we can write it as follows:

$= {( \sqrt{2} a + \sqrt{3} b)}^{3}$

Hence the given equation has been factorised.