Math, asked by starny09, 1 year ago

pls solve it



it's urgently required...

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Answers

Answered by Anonymous
0
Addition : -

(i) = 12+(-11)
= 12-11 = 1
(ii) = 9√2 - 3√2
= (9-3) √2
= 6√2

Subtraction :-
(i) = 12-3/4
= 48-3/4
= 45/4 = or 11.25

(ii) = 2√5 - 9√-5
= -7√5

Multiplication :-

(i) = 9√2 × 5√7
= 45√14
(ii) = 9√2 × -3√2
= -27 × (√2)²
= -27 × 2
= - 54

Division :-
(i) =
 \:  \:  \:  \frac{12}{9 \sqrt{2} }  \\  \frac{12(9 \sqrt{2}) }{9 \sqrt{2}  \times 9 \sqrt{2} }  =  \frac{108 \sqrt{2} }{81 \times 2}  = \frac{108 \sqrt{2} }{162}
(ii) =
 \frac{ - 11}{3 \sqrt{11} }  =  \frac{ - 11 \times 3 \sqrt{11} }{3 \sqrt{11} \times  3\sqrt{11}  } =  \frac{ - 33 \sqrt{11} }{9 \times 11}   =  \frac{ - 33 \sqrt{11} }{99}


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