pls solve it or atleast explain the meaning of last line...
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let the same common difference of two A.P's is d
given that the first term of first AP and second AP are 2 and 7 respectively then the AP is
2,2+d,2+2d,2+3d.... and
7,7+d,7+2d,7+3d.....
now 10th terms of first and second AP are 2+9d and 7+9d
d = 7+9d-(2+9d)=5
also 21st term of first and second AP are 2+20d and 7+20d
d=7+20d-(2+20d)=5
also if an and bn are nth term of 1st and 2nd ap
an=[7+(n-1)d]-[2+(n-1)d] =5
hence the difference between any two corresponding terms of such AP's
is the same as the difference between their first terms
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