Question

pls solve it ......pls​

Answer 1

Solution:

log[(a+b)/2] = 1/2(loga+log b)

=> 2log[(a+b)/2] = loga+logb

=> log[(a+b)/2]² = log(ab)

/* i)n log m = log mⁿ

ii) logm+logn = logmn */

=> [(a+b)/2]² = ab

=> (a+b)²/4 = ab

=> (a+b)² = 4ab

=> a²+b²+2ab-4ab = 0

=> a²+b²-2ab = 0

=> (a-b)² = 0

=> a-b = 0

=> a = b

Therefore,

Option (2) is correct

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