Question

pls solve it properly...exponents​

Answer 1

Answer:

128/27

Step-by-step explanation:

HEYA MATE HERE YOU GO..

First you need to do all number in multiplication form like 3/2×3/2×3/2 then there is division so you need to reciprocal it then it will be like

3/2×3/2×3/2×4/3×4/3×4/3×4/3×4/3×4/3×1/2×1/2

then you cancel all the divisible terms then you will finally get 128/27 as your answer.

HOPE YOU UNDERSTAND ♥️ IF YES THEN PLEASE MARK IT AS THE BRAINLIEST ANSWER..

Answer 2

Answer:

128/27

Step-by-step explanation:

{(3/2)^3}÷{(3/4)^6}×{(1/2)^2}

={(3^3)/(2^3)}×{(4^6)/(3^6)}×{(1^2)/(2^2)}

={(3^3)/(2^3)}×{(2^12)/(3^6)}×{1/(2×2)}

={(3×3×3)/(2×2×2)}×{(2×2×2×2×2×2×2×2×2×2×2×2)/(3×3×3×3×3×3)}×{1/(2×2)}

=(1/1)×{(2×2×2×2×2×2×2×2×2)/(3×3×3)}×{1/(2×2)} (by cancelling 3×3×3and2×2×2)

{(2×2×2×2×2×2×2)/(3×3×3)×{1/1} (by cancelling 2×2)

so, {(2^7)/(3^3)} i.e.128/27

hope it will help you!!!