Question

pls solve it quickly​

Answer 1

given:

XN||AB and XN||AC

to prove:

TX^2 = TB*TC

proof:

In triangle TXM, since BN||XM , by bpt

TB\TX = TN\TM ....................(i)

XN||AC

So , XN||CM

In triangle TMC , since XN||CM, by BPT,

TX\TC = TN\TM .........................(ii)

From (i) and (ii) ,

TB\TX = TX\TC

Therefore TX^2 = TB*TC

Hence proved.

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