Question

pls solve it roughly​

Answer 1

Answer:

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Step-by-step explanation:

i know the answer but i wont tell...

dont feel bad but u should give your test honestly....

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Answer 2

Given:-

• Length of rectangle = 40 cm
• Diagonal of rectangle = 41 cm

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To find:-

• Perimeter of rectangle

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$\huge \tt \: ☃\:SolutioN$

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Figure is in image

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In ∆ ABC

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Formula used:-

Pythagoras theorem that is

☘ (Base)² + (Perpendicular)² = (Hypotenuse)²

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Base = BC = To find

Perpendicular = AB = 40 cm

Hypotenuse = AC = 41 cm

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Put the values in formula

⇒(BC)² + (40)²= (41)²

⇒(BC)² = (41)² - (40)²

⇒(BC)² = 1681 -1600

⇒(BC)² = 81

⇒BC = $\sqrt{81}$

⇒BC = 9 cm

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✢ BC is breadth of rectangle and BC is side of triangle.

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So, Breadth of rectangle = 9 cm

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☘ Perimeter of rectangle = 2(l + b)

⇒2 × (40 + 9)

⇒80 + 18

⇒98 cm

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Thus, Perimeter of rectangle is 98 cm.