Question

pls solve... it's urgent.
if correct I'll mark as brainiest​

Answer 1

Step-by-step explanation:

$\huge\boxed{\fcolorbox{black}{pink}{Answer}}$

Given :- root 1 - cos theta / 1 + cos theta = codec theta - cot theta

Solution:- upaar h

Answer 2

$\sf\large\underline\blue{Given:}$

$\tt{\implies \sqrt{\dfrac{1-cos\theta}{1+cos\theta}}=cosec\theta-cot\theta}$

$\sf\large\underline\blue{Solution:}$

To prove LHS=RHS at first we have to rationalise by applying formula of trigonometry:]

$\sf\large\underline\blue{Here\:we\: solve\:by\:LHS:}$

$\tt{\implies \sqrt{\dfrac{1-cos\theta}{1+cos\theta}}}$

$\tt{\implies \sqrt{\dfrac{1-cos\theta}{1+cos\theta}*\dfrac{1-cos\theta}{1-cos\theta}}}$

$\tt{\implies \sqrt{\dfrac{(1-cos\theta)^2}{1-cos^2\theta}}}$

$\tt{\implies \sqrt{\dfrac{(1-cos\theta)^2}{sin^2\theta}}}$

$\tt{\implies \dfrac{1-cos\theta}{sin\theta}}$

$\tt{\implies \dfrac{1}{sin\theta}-\dfrac{cos\theta}{sin\theta}}$

$\tt{\implies cosec\theta-cot\theta}$

$\sf\large{Hence,}$

$\tt\large\green{L.H.S=R.H.S}$