pls solve it....surface area and volumes
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Let let the ages of the three cubes be 3x + 4 x + 5 x respectively
show volume of 3 cubes = 3 x cube + 4 x cube + 5 x cube equals 216 x cube cm cube
therefore volume new cube =volume of three cubes
a^3=216x^3
a=6x
diagonal of a new cube equals 12 root 3 cm
root a^2+a^2+a^2=12root3cm
root3a=12root3
a=12
×=2
therefore3×2=6; 4×2=8 therefore the ages of three cubes are eight 10 6 respectively
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