Question

pls solve its urgent pls​

Answer 1

Answer:

7^2x÷7^7 / 7^4x =7^3

7^2x-7-4x =7^3 (a^x÷a^y=a^x-y)

7^-(7+2x) =7^3

-(7+2x)=3. (a^x=a^y

{x=y}

-7 -2x =3

-2x=-3-7

-2x=-10

x=5

Answer 2

Answer:

x= -5

Step-by-step explanation:

for divide I will use "/"

we know y^x/y^z = y^(x-z)

=> Simplify numerator

=> 7^(2x-7)/7^4x

=> 7^(2x-7-4x) which is equal to 7^3

=> The powers of LHS And RHS should be equal.

=> 2x-7-4x = 3

=> -7-2x = 3

=> -2x = 10

=> x = 10/(-2)

=> x = -5

Hope it helps...

Please mark as Brainliest☺☺