Question

pls solve : M^2 + 2m - 3

Answer 1

Answer:

m=1 , m=-3

Step-by-step explanation:

m=(-b+-root(b^2-4ac))/2a

m= (-2+-root(2^2-4×1×-3))/2×1

m=-2+-root(16)/2

m= -2+-4/2

m=1 , m=-3

Answer 2

Answer:

$\huge\orange{\boxed{m = 1 \: \: or \: -3}}$

Step-by-step explanation:

${m}^{2} + 2m - 3 = 0$

${m}^{2} - 1m + 3m - 3 = 0$

$m(m - 1) + 3(m - 1) = 0$

$( m- 1) (m + 3) = 0$

$(m - 1) = 0 \: \: or \: \: (m + 3) = 0$

$if \: (m - 1) = 0 \\ \: \: \: then\: \: m = 1$

$and \: if \: (m + 3) = 0 \\ \: \: \: then \: \: m = - 3$

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