Question

Pls solve maths class 9 polynomial

Answer 1

Answer:

Let f(z) = az³+4z²+3z-4 zero of the polynomial (z-3) = 3

(since,z-3-0 → z=3)

=

So,replacing z by 3, f(3) = a(3)³+4(3)²+3(3)-4

f(3) = = 27a+36+9-4 f(3) = 27a+41

Let g(z) = z³-4z+a

zero of the polynomial (z-3) = 3

(since,z-3-0 → z=3)

So,replacing z by 3, g(3) = (3)³-4(3)+a

>g(3) = 27-12+a

=

⇒ g(3) = 15+a

Given that the two polynomials leaves same remainder when divided by z-3

So,g(3)=f(3)

=> 15+a 27a+41

→ 15-41 = 27a - a

⇒-26 = 26a

⇒ a = -1.

Step-by-step explanation:

I brother iam 13 age nice to meet u