pls solve no 5 and help.me out if you can plsss
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Angle M = angle N ( = 90 degrees)
PA = PA (common)
PM = PN ( given )
Therefore by RHS property both triangles are congruent
So angle MAP = angle NAP
Therefore AP bisects angle A
PA = PA (common)
PM = PN ( given )
Therefore by RHS property both triangles are congruent
So angle MAP = angle NAP
Therefore AP bisects angle A
jyotikoul75:
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