CBSE BOARD XII, asked by sudiptavijay04, 9 months ago

pls solve
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Answered by LUSTGUY
5

Given: x=8+12 t-t^3

We know v=dx/dt

and a = dv /dt

So, v= 12 - 3t^2

and a = -6t

At t = 2s

v= 0 and a = -6

t = 2s

a = - 12m/s^2

so retardation of the particle = 12m/s2

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