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Given: x=8+12 t-t^3
We know v=dx/dt
and a = dv /dt
So, v= 12 - 3t^2
and a = -6t
At t = 2s
v= 0 and a = -6
t = 2s
a = - 12m/s^2
so retardation of the particle = 12m/s2
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