Question

pls solve on white paper
Ques 5​

Answer 1

Answer:

2

Explanation step by step :

$sec50°sin40° + cos40° cosec50° \\ </p><p> = cosec(90°-50°) \times \frac{1}{cosec40°} + \frac{1}{sec40°} \times sec(90°-50°)</p><p> \\ = cosec40° \times \frac{1}{cosec40°} + \frac{1}{sec40°} \times sec40° \\ = 1 + 1 \\ = 2$

Remember =>

cosec (90°-A)=secA

sec (90°-A)=cosecA

sinA=1/cosecA

cosA=1/secA