Pls solve only [a]
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3rd Equation of motion
v= final velocity
u= initial velocity
a=acceleration
s=distance
v^2-u^2 =2as
S= (u+v/2)×t
As per 1st equation
S= (u+v/2)×(v-u/a)
= v^2 -u^2/2a
2aS = v^2-u^2
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check the photo for answer
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