Math, asked by mizzzcutiepie, 1 month ago

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Answered by XxSadToxicBoyxX
0

1]Given,

Given, mass of rock = m = 10 kg

Given, mass of rock = m = 10 kg height = 5m

Given, mass of rock = m = 10 kg height = 5m

Given, mass of rock = m = 10 kg height = 5m using conservation of mechanical energy

Given, mass of rock = m = 10 kg height = 5m using conservation of mechanical energy loss in potential energy = gain in kinetic energy

Given, mass of rock = m = 10 kg height = 5m using conservation of mechanical energy loss in potential energy = gain in kinetic energy K.E=mgh=10×10×5=500J

Given, mass of rock = m = 10 kg height = 5m using conservation of mechanical energy loss in potential energy = gain in kinetic energy K.E=mgh=10×10×5=500J 1/2m×v

Given, mass of rock = m = 10 kg height = 5m using conservation of mechanical energy loss in potential energy = gain in kinetic energy K.E=mgh=10×10×5=500J 1/2m×v 2

Given, mass of rock = m = 10 kg height = 5m using conservation of mechanical energy loss in potential energy = gain in kinetic energy K.E=mgh=10×10×5=500J 1/2m×v 2 =500

Given, mass of rock = m = 10 kg height = 5m using conservation of mechanical energy loss in potential energy = gain in kinetic energy K.E=mgh=10×10×5=500J 1/2m×v 2 =500 v

Given, mass of rock = m = 10 kg height = 5m using conservation of mechanical energy loss in potential energy = gain in kinetic energy K.E=mgh=10×10×5=500J 1/2m×v 2 =500 v 2

Given, mass of rock = m = 10 kg height = 5m using conservation of mechanical energy loss in potential energy = gain in kinetic energy K.E=mgh=10×10×5=500J 1/2m×v 2 =500 v 2 =100

Given, mass of rock = m = 10 kg height = 5m using conservation of mechanical energy loss in potential energy = gain in kinetic energy K.E=mgh=10×10×5=500J 1/2m×v 2 =500 v 2 =100 v=10m/s

Given, mass of rock = m = 10 kg height = 5m using conservation of mechanical energy loss in potential energy = gain in kinetic energy K.E=mgh=10×10×5=500J 1/2m×v 2 =500 v 2 =100 v=10m/sspeed of rock is 10 m/s and its kinetic energy is 500 JGiven,

Given, mass of rock = m = 10 kg

Given, mass of rock = m = 10 kg height = 5m

Given, mass of rock = m = 10 kg height = 5m

Given, mass of rock = m = 10 kg height = 5m using conservation of mechanical energy

Given, mass of rock = m = 10 kg height = 5m using conservation of mechanical energy loss in potential energy = gain in kinetic energy

Given, mass of rock = m = 10 kg height = 5m using conservation of mechanical energy loss in potential energy = gain in kinetic energy K.E=mgh=10×10×5=500J

Given, mass of rock = m = 10 kg height = 5m using conservation of mechanical energy loss in potential energy = gain in kinetic energy K.E=mgh=10×10×5=500J 1/2m×v

Given, mass of rock = m = 10 kg height = 5m using conservation of mechanical energy loss in potential energy = gain in kinetic energy K.E=mgh=10×10×5=500J 1/2m×v 2

Given, mass of rock = m = 10 kg height = 5m using conservation of mechanical energy loss in potential energy = gain in kinetic energy K.E=mgh=10×10×5=500J 1/2m×v 2 =500

Given, mass of rock = m = 10 kg height = 5m using conservation of mechanical energy loss in potential energy = gain in kinetic energy K.E=mgh=10×10×5=500J 1/2m×v 2 =500 v

Given, mass of rock = m = 10 kg height = 5m using conservation of mechanical energy loss in potential energy = gain in kinetic energy K.E=mgh=10×10×5=500J 1/2m×v 2 =500 v 2

Given, mass of rock = m = 10 kg height = 5m using conservation of mechanical energy loss in potential energy = gain in kinetic energy K.E=mgh=10×10×5=500J 1/2m×v 2 =500 v 2 =100

Given, mass of rock = m = 10 kg height = 5m using conservation of mechanical energy loss in potential energy = gain in kinetic energy K.E=mgh=10×10×5=500J 1/2m×v 2 =500 v 2 =100 v=10m/s

Given, mass of rock = m = 10 kg height = 5m using conservation of mechanical energy loss in potential energy = gain in kinetic energy K.E=mgh=10×10×5=500J 1/2m×v 2 =500 v 2 =100 v=10m/sspeed of rock is 10 m/s and its kinetic energy is 500 J

2] When an object falls freely towards the ground, its potential energy decreases, and kinetic energy increases; as the object touches the ground, all its potential energy becomes kinetic energy. As the object hits the hard ground, all its kinetic energy becomes heat energy and sound energy.06-

Answered by PRINCE100001
3

Step-by-step explanation:

Given :

  • A man drops a 10 kg rock from the top of a 5 m ladder.

To Find :

  • Kinetic energy of rock when it reaches the ground

Theory :

  • • Work energy theorem

The change in kinetic energy of a particle is equal to the work done by the net force.

\bf\green{W=\triangle\:K.E.}

  • • Law of conservation of mechanical energy

The sum of the potential energy and kinetic energy is called the total mechanical energy.

\bf\blue{\triangle\:U+\triangle\:K.E.}

Solution:

We have to find Kinetic energy of rock when it reaches the ground.

By Work energy theorem

\sf{W=\triangle\:K.E.}

\sf\implies\:W_{Gravity}=K.E_{final}-KE_{initial}

\sf\implies\:mgh=\dfrac{1}{2}mv^2-0

Put the given values

\sf\implies\dfrac{1}{2}mv^2=10\times10\times5

\sf\implies\:KE_{final}=500J

Therefore , Kinetic energy of rock when it reaches the ground is 500 J.

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