Question

pls solve quadratic equation 49x^2+21x+9/4=0​
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Answer 1

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Step-by-step explanation:

a=49, b=21, c=9/4

x = −b±√b2−4ac

           2a

x = −(21)±√(21)²−4×49×9/4  

            2×49

x = −(21)±√441-441  

            2×49

x = −21±√0

      98

x = −0.214286