pls solve que no.5,8,9,10
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for the 5th one make an equation that is
2x-10 + x/2=180 (Since they form a linear pair)
solve the value for x then put the values in 2x-10 and x/2 whichever comes big tick that answer!
sum of supplementary angles = 180
Sum of complementary angles = 90
So now find the difference!
let angle 2 and angle 3 be x
ANGLE 1 WILL BE x/4
Now : x+x+x/4= 180. find the measure of x
and the angle 2 measurement.
As L is parallel to BC
Therefore Angle 2 and Angle B are alternate interior angles which are equal
2x-10 + x/2=180 (Since they form a linear pair)
solve the value for x then put the values in 2x-10 and x/2 whichever comes big tick that answer!
sum of supplementary angles = 180
Sum of complementary angles = 90
So now find the difference!
let angle 2 and angle 3 be x
ANGLE 1 WILL BE x/4
Now : x+x+x/4= 180. find the measure of x
and the angle 2 measurement.
As L is parallel to BC
Therefore Angle 2 and Angle B are alternate interior angles which are equal
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