pls solve question 23 fast
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5^x+5^x-1=5^4+5^3(750=5^4+5^3)
x+x-1=4+3 (since Base in both sides are same i.e. 5 so we can remove the Base and keep the exponents because say for eg. 5^x=5^1 ;x will be 1.Verification:5^1=5^1;it's similar for all others too)
2x=8
x=4
Hope it helps:)
verification :
5^x+5^x-1=750
(having taken out x=4)
5^4+5^4-1=750
5^4+5^3=750
750=750
LHS=RHS
So verified.
x+x-1=4+3 (since Base in both sides are same i.e. 5 so we can remove the Base and keep the exponents because say for eg. 5^x=5^1 ;x will be 1.Verification:5^1=5^1;it's similar for all others too)
2x=8
x=4
Hope it helps:)
verification :
5^x+5^x-1=750
(having taken out x=4)
5^4+5^4-1=750
5^4+5^3=750
750=750
LHS=RHS
So verified.
Thatsomeone:
Look your inbox
But the way I have done is absolutely right.
Is my book wrong??
May be but this is hit and try method
it is useful in MCQ only
I have send you my answers link in inbox look once
https://math.stackexchange.com/questions/1675978/what-is-process-function-to-cancel-base-in-value-with-exponential
Have a look at this link.
The logic is verified here
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Answered by
1
5^x + 5^x - 1 = 750
5^x + 5^x × 5^-1 = 750
5^x ( 1 + 1/5 ) = 750
5^x × 6/5 = 750
5^x = 750 × 5/6
5^x = 125 × 5
5^x = 5^3 × 5
5^x = 5^4
x = 4
5^x + 5^x × 5^-1 = 750
5^x ( 1 + 1/5 ) = 750
5^x × 6/5 = 750
5^x = 750 × 5/6
5^x = 125 × 5
5^x = 5^3 × 5
5^x = 5^4
x = 4
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