pls solve question no 11
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Hello.,
3a = x
5b = y
4c =z
So,
If x +y + z = 0
Then x³ +y³+z³ = 3xyz.
So,
Given that
3a + 5b + 4c = 0
Therefore :
(3a)³+(5b)³+(4c)³ = 3*3a*5b*4c = 180 abc
27a³ +125b³ + 64c³ = 180abc
Hence, proved
Hope this will be helping you ✌️
3a = x
5b = y
4c =z
So,
If x +y + z = 0
Then x³ +y³+z³ = 3xyz.
So,
Given that
3a + 5b + 4c = 0
Therefore :
(3a)³+(5b)³+(4c)³ = 3*3a*5b*4c = 180 abc
27a³ +125b³ + 64c³ = 180abc
Hence, proved
Hope this will be helping you ✌️
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