Question

Pls solve Question no. 11
It's urgent
Pls....

Answer 1

Answer:

Step-by-step explanation:

Angle b =90°

AC^2=BC^2+AB^2....EQ.1

LET AB=X....EQ2

AC=25-x.....EQ3

FROM EQ 1,2 AND 3

(25-x)^2=5^2+x^2

x^2 +625-50x=25+x^2

Cancel x from both sides

625-50x=25

Transfer 25 and -50x both other side

625-25=50x

600=50x

Divide both side by 50

600/50=50x/50

x=12

25-x=25-12=13 now you can find all trigonometric ratios because you have base, perpendicular and hypotaneous

Answer 2

sinA=1/3

cosA=2/3

tanA=1/2

cosecC=3/2

cotC=1/2

secC=3

Step-by-step explanation:

AC+AB=25,BC=5

LET AC=25-AB

IN ∆ABC B=90

AC²=AB²+BC²

AC=√AB²+BC²

25-AB=AB+5

25-5=AB+AB

20=2AB

AB=20/2

AB=10

AC+AB=25

AC=25-AB

AC=25-10

AC=15