Pls solve question number 7
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6ab-b^2+12ac-2bc;
=>6ab+12ac-b^2-2bc.
=>6a(b+2c)-b(b+2c).
=>(6a-b)(b+2c)=0.
=>a=b/6 or b=-2c.
=>6ab+12ac-b^2-2bc.
=>6a(b+2c)-b(b+2c).
=>(6a-b)(b+2c)=0.
=>a=b/6 or b=-2c.
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See in the attachment .
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