pls solve question2&3
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hey mate here is your answer 3
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now atoms contain by 20g Ca = 3.011* 10^23
than 6.022*10^23 Na atoms = 23 g Na
so 1 Na atom = 23/6.022*10^23
than 3.011*10^23 Na atoms =
23/6...*3.011*10^23= 11.5g
than 6.022*10^23 Na atoms = 23 g Na
so 1 Na atom = 23/6.022*10^23
than 3.011*10^23 Na atoms =
23/6...*3.011*10^23= 11.5g
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