Math, asked by saloni27, 1 year ago

pls solve questions 88,91

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Answered by lekhahasa

88) (√11-√5)/(√11+√5)
rationalising factor of (√11+√5) is (√11-√5)
⇒[(√11-√5)×(√11-√5)]/[(√11+√5)×(√11-√5)=(√11-√5)²/(√11)²-(√5)²
=(11+5-2√55)/11-5
=(16-2√55)/6
=[2(8-√55)]/6
=(8-√55)/3

91) 1/(1+√2-√3)
rationalising factor of [1+(√2-√3)] is [1-(√2-√3)]
⇒{1/[1+(√2-√3)]}×{[1-(√2-√3)]/[1-(√2-√3)]}=(1-√2-√3)/[1²-(√2-√3)²
=(1-√2-√3)/(1-2-3+2√6)
=(1-√2-√3)/(2√6-4).

saloni27: first one is right but the ans.of second question is 1+√2+√6/2+4

kvnmurty: 2nd qn.. the denominator still has irrational number.. should rationalize that further.

kvnmurty: perhaps you could write the answer here

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