Question

Pls solve quick....
I need it ASAP

Answer 1

Answer:

I don't know

Step-by-step explanation:

because I in class 6th

Answer 2

Answer:

Step-by-step explanation:

we have to obtain all other zeros of the polynomial x⁴ + 2x³ - 13x² - 38x - 24, if two of its zeros are -1 and -2.

here, -1, -2 are zeros of x⁴ + 2x³ - 13x² - 38x - 24.

so, (x + 1) and (x + 2) are factors of x⁴ + 2x³ - 13x² - 38x - 24 .

so, (x + 1)(x + 2) or x² + 3x + 2, is also a factor of x⁴ + 2x³ - 13x² - 38x - 24 .

so, on dividing x⁴ + 2x³ - 13x² - 38x - 24 by x² + 3x + 2 we will get another factor.

x² + 3x + 2)x⁴ + 2x³ - 13x² - 38x - 24 ([x² - x-12]

x⁴ + 3x³ + 2x²

---------------------

-x³ - 15x² - 38x

- x³ - 3x² - 2x

---------------------

-12x² - 36x -24

-12x² - 36x - 24

-------------------------

0

so, another factor of x⁴ + 2x³ - 13x² - 38x - 24 is (x² - x - 12)

then, (x² - x - 12) = 0

or, x² - 4x + 3x - 12 = 0

or, x(x - 4) + 3(x - 4) = 0

or, (x + 3)(x - 4) = 0

or, x = -3 and 4

hence, another zeros are ; -3 and 4