Question

pls solve qustion no 38....

Answer 1

$\mathfrak {\underline {\underline {Answer :}}}$

$<b>The velocity of A₁ is 0.6 v</b>$

$\mathfrak {\underline {\underline {Explanation :}}}$

Join A₀A₁ and A₁A₂ .

By the geometry of the two rhombus,

$\sf {\implies \dfrac {3x}{2x} = \dfrac{A_0A_1}{A_1A_2}}\\\\\\</p><p></p><p></p><p>\sf{\implies \dfrac{A_0A_1}{A_1A_2} = \dfrac {3}{2}}$

The hing A₁ will pull the segment A₀A₁ .

The hing A₂ will pull the segment A₀A₂ .

$\sf {\implies\dfrac {A_0A_1}{A_1A_2 + A_0A_1} = \dfrac{3}{2 + 3}}\\\\\\</p><p></p><p></p><p></p><p>\sf {\implies \dfrac {A_0A_1}{A_1A_2 + A_0A_1} = \dfrac{3}{5}}$

The vertex A₂ moves with a speed v.

So, the other vertices will move in a ratio similar to the lengths of the respective segments.

$\sf {\therefore \dfrac {v_{A_1}}{v_{A_2}} = \dfrac {3}{5}}\\\\\\</p><p></p><p></p><p></p><p>\sf {\implies v_{A_1} = \dfrac {3v_{A_2}}{5}}\\\\\\</p><p></p><p></p><p></p><p>\sf {\implies v_{A_1} = \dfrac {3v}{5}}\\\\\\</p><p></p><p></p><p></p><p>\sf {\implies v_{A_1} = 0.6 v}$