Question

pls solve soon as possible pls​

Answer 1

Answer:

$\boxed{\sf Present \ ages = 20, 80}$

Given:

Present age of father = Four times the age of his son

Age of father after 10 years = Three times the age of his son

To Find:

Present ages of father and his son.

Step-by-step explanation:

Let the present age of son be 'x' years

So,

Present age of father = 4x years

Age of son after 10 years = x + 10

Age of father after 10 years = 3(x + 10) OR = 4x + 10

$\sf \implies 3(x + 10) = 4x + 10 \\ \\ \sf \implies 3x + 30 = 4x + 10 \\ \\ \sf \implies 3x + 30 - 10 = 4x \\ \\ \sf \implies 3x + 20 = 4x \\ \\ \sf \implies 4x = 20 + 3x \\ \\ \sf \implies 4x - 3x = 20 \\ \\ \sf \implies x = 20$

So,

Present age of son = x

= 20 years

Present age of father = 4x

= 4 × 20

= 80 years

Answer 2

Let the present age of son be x

the present age of father be 4x

After 10 years, son will be (x+10)

After 10 years, father will be 3(x+10)

ATP

3(x+10) = 4x+10

=) 3x+30 = 4x+10

=) 30-10 = 4x-3x

=) 20 = x

Ans:- Present age of son = 20yrs

Present age of father = (4×20) = 80yrs

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