Question

pls solve teachers or mam​

Answer 1

Step-by-step explanation:

here

mark

me

Brainlest

Answer 2

Answer:

$a = 1 \\ b = \frac{ - 5}{6}$

Step-by-step explanation:

Do rationalization

$\frac{ \sqrt{2} + \sqrt{3} }{3 \sqrt{2} - 2 \sqrt{3} } \times \frac{3 \sqrt{2} + 2 \sqrt{3} }{3 \sqrt{2} + 2 \sqrt{3} } \\ \\ = \frac{3 \sqrt{2} \sqrt{2} + 2 \sqrt{2} \sqrt{3} + 3 \sqrt{2} \sqrt{3} + 2 \sqrt{3} \sqrt{3} }{( {3 \sqrt{2}) }^{2} - ( {2 \sqrt{3}) }^{2} } \\ \\ = \frac{3 \times 2 + 2 \sqrt{6} + 3 \sqrt{6} + 6}{18 - 12} \\ \\ = \frac{12 + 5 \sqrt{6} }{6} \\ \\ = \frac{12}{6} + \frac{5 \sqrt{6} }{6}$

$2 + \frac{5 \sqrt{6} }{6} = 2a - b \sqrt{6} \\ \\ compare \: \\ \\ 2a = 2 \\ \\ a = 1 \\ \\ - b \sqrt{6} = \frac{5 \sqrt{6} }{6} \\ \\ b = - \frac{5}{6}$

Hope it helps you.